(x+5)(x-4)=x^2-15

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Solution for (x+5)(x-4)=x^2-15 equation:


Simplifying
(x + 5)(x + -4) = x2 + -15

Reorder the terms:
(5 + x)(x + -4) = x2 + -15

Reorder the terms:
(5 + x)(-4 + x) = x2 + -15

Multiply (5 + x) * (-4 + x)
(5(-4 + x) + x(-4 + x)) = x2 + -15
((-4 * 5 + x * 5) + x(-4 + x)) = x2 + -15
((-20 + 5x) + x(-4 + x)) = x2 + -15
(-20 + 5x + (-4 * x + x * x)) = x2 + -15
(-20 + 5x + (-4x + x2)) = x2 + -15

Combine like terms: 5x + -4x = 1x
(-20 + 1x + x2) = x2 + -15

Reorder the terms:
-20 + 1x + x2 = -15 + x2

Add '-1x2' to each side of the equation.
-20 + 1x + x2 + -1x2 = -15 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-20 + 1x + 0 = -15 + x2 + -1x2
-20 + 1x = -15 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-20 + 1x = -15 + 0
-20 + 1x = -15

Solving
-20 + 1x = -15

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 1x = -15 + 20

Combine like terms: -20 + 20 = 0
0 + 1x = -15 + 20
1x = -15 + 20

Combine like terms: -15 + 20 = 5
1x = 5

Divide each side by '1'.
x = 5

Simplifying
x = 5

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